Phantom Lorentz force Paradox
16 July 2012
I have exposed an inconsistency of
Ampere-Maxwell equation, in the article
“Displacement Current Paradox” http://pengkuanem.blogspot.com/2012/07/displacement-current-paradox.html
This equation states that displacement
current creates magnetic field and EMF. However, “Displacement Current Paradox”
shows that this EMF would violate the energy conservation law.
Magnetic field has 2 properties, EMF and
Lorentz force. Let us study the Lorentz force created by magnetic field associated
to displacement current. The Figure
1 shows a round plate capacitor charged by an alternate
current Ic, and a wire
loop in which circulates a constant Il.
The varying charge of the capacitor creates a displacement current and then a
magnetic field, which in turn, exerts a Lorentz force on the current loop.
Please read the following document
Used documents links
(1) Synthesis of the inconsistency
of the Lorentz force law http://pengkuanem.blogspot.com/2012/04/synthesis.html
(4) Displacement Current
Paradox http://pengkuanem.blogspot.com/2012/07/displacement-current-paradox.html
hmm, comment didn't post. Trying to get your attention...
ReplyDeleteIf you replace the capacitor with just a solid wire, the force on the loop will not change. The force on the loop is the same force a loop whose axis is out-of-the-page feels next to a wire with current moving upwards (dc).
The one thing you forgot to account for is that for any motion of the loop (f*d) will result in a back-emf pushing against the current in the wire. It always works out that any work you take from the loop of wire nearby, will result in the current carrying wire (or changing field carrying capacitor) to feel a resistance (so-to-speak...it will be like a voltage drop). The result is, you'd need to do work from the power source to keep the current going the same way.
I have worked out the math a while back that even if you create a huge force, and move the coil a tiny tiny bit, it is the same result as a lower force, moving the coil more.
The situation you thought up, comes out the same way if you simply have an electromagnet attached to an AC source. With a DC electromagnet overhead moving back and forth like a piston doing some work. Try it out :)
Thanks for your comment.
DeleteIf you replace the capacitor with a wire, the wire will feel a force opposite to that on the loop. So, the movement will do a work on the loop and an opposite work on the wire. This is how Lorentz force keeps energy balanced for solid wire and why I choose capacitor here. Displacement current violates this balance. Your objection does not save the situation.
Now we're talking:
Deletehere is a question though:
we know that the displacement current produces a magnetic field. In fact, it isn't that the displacement current produces a magnetic field, it's that when there is a change of electric field, there is a magnetic field in that space - and the change of electric field Maxwell called a current [he was actually thinking along the lines of the aether]
Now, when this magnetic field pushes something, how does that something push back? It doesn't make sense that you are pushing against a virtual flow of current.
In the above case, all I am saying is that the work done on the circuit to the right, will appear as electrical resistance in the circuit on the left (assuming it is clamped down). There may be something else happening all together, and that is what I'm working on.
In fact, my point is that displacement current does not exist and my paradoxes are devised to show this. I think that magnetic field is the space trace of moving electrons. Electric field, even varying, is not moving electrons. Thus, magnetic force reaction can only apply on electrons, static or moving. As displacement current is not electrons, it does not receive force. This is the fundamental reason these paradoxes hold.
Deletebtw, I've been writing to
Deletetitang@gmail.com
which is the email in your old papers. Did it change?
The existence of displacement current is what results in the e/m wave equation.
Furthermore, the magnetic field created by the displacement current has been verified experimentally many times (as far as I know).
how it is derived and how it behaves seems to make sense
http://farside.ph.utexas.edu/teaching/em/lectures/node46.html
only this action reaction bit is off...but I think it might be from the wrong expectation...
check this out as well
Deletehttp://teacher.nsrl.rochester.edu/phy122/Lecture_Notes/Chapter35/chapter35.html
My address is "titang" with "78". titang78@gmail.com
DeleteIt is possible that I have given it without 78 by error.
Displacement current is an invention of Maxwell without experimental proof. In the documents from your links, no experimental proof is given. Until now, no formal experimental proof has been known. In fact, the wave equation he derived is wrong because of this. I have written several articles about the inconsistency of the wave equation:
http://pengkuanem.blogspot.com/2013/01/energy-density-of-electromagnetic-wave.html
EM wave equation gives a solution whose energy density goes to infinity at r=0.
http://pengkuanem.blogspot.com/2012/12/electromagnetic-wave-energy-flux.html
EM wave equation gives a solution whose energy density is variable with distance and goes to infinity at r=0.
http://pengkuanem.blogspot.com/2012/08/can-em-wave-go-forward-back.html
EM wave equation gives a solution whose velocity is variable with distance and goes to infinity at some points and becomes negative near the source.
http://pengkuanem.blogspot.com/2012/07/electromagnetic-wave-paradox.html
EM wave equation gives a solution whose velocity is variable with distance from the source.
If we have a capacitor in a circuit, and displacement current can not produce a reactionary force, then even if we use your corrected magnetic force equations, does not the self force on the primary circuit become unbalanced and thus violate Newton's third law? It seems the circuits could produce a force upon itself and move? Is this correct?
ReplyDeleteDr. Jaynes
What I'm showing here is that displacement current does not exist. If there is magnetic field within the capacitor, it is caused by real current in the circuit. Only moving electrons create magnetic field, not varying electric field. If one uses my corrected law, one has to pair the current in the circuit and the test current I1. This way the forces are balanced and Newton's third law is respected.
DeleteFor the self force on the circuit, one must not use the magnetic field from displacement current, then, there will not be unbalanced force.
In fact, one has to compute the magnetic field within the capacitor from the current of the circuit, but not from the varying electric field. The reaction force is not beared by the void, but by the current.
Also, as the magnetic field of the current in the circuit is not equal to that of the electrical field generated displacement current, the displacement magnetic field within the capacitor is not correct.